On 2011-02-18 07:32:48 +0100, Robert Abiad said:

> Dear Folks,
> 
> I'm finding that hist has problems computing on 2d arrays.
> 
>     import  numpy
>     import  pylab
>     mu,  sigma  =  2,  0.5
>     v  =  numpy.random.normal(mu,sigma,160000)
>     pylab.hist(v,  bins=1000,  normed=1)
> 
> This works without any problems.  But if you try this:
> 
>     w=v.reshape(400,400)
>     pylab.hist(w,  bins=1000,  normed=1)
> 
> it doesn't come back on my machine until all of memory is used up.  However:
> 
>     n,bins = numpy.histogram(w,bins=1000,normed=1)
> 
> works just fine.

That's by design. For a n x m array, pylab.hist is doing m times a 
histogram of the n items subarray and then tries to plot them somehow 
on top of each other. The detail I don't know, but most likely you want 
to do
pylab.hist(w.flatten(), ....)
to get a 1-dim array that you want to fill in ONE histogram. (for 
example for image arrays).

HTH,
Michael

> 
> 
> 
> ------------------------------------------------------------------------------
> The ultimate all-in-one performance toolkit: Intel(R) Parallel Studio XE:
> Pinpoint memory and threading errors before they happen.
> Find and fix more than 250 security defects in the development cycle.
> Locate bottlenecks in serial and parallel code that limit performance.
> http://p.sf.net/sfu/intel-dev2devfeb




------------------------------------------------------------------------------
The ultimate all-in-one performance toolkit: Intel(R) Parallel Studio XE:
Pinpoint memory and threading errors before they happen.
Find and fix more than 250 security defects in the development cycle.
Locate bottlenecks in serial and parallel code that limit performance.
http://p.sf.net/sfu/intel-dev2devfeb
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