When using AC modeling, the power flow is complex and it is not that same at the two ends of a branch, so you may want to use the average MVA as the flow.
define_constants; r = runpf(…); Af = sqrt(r.branch(:, PF)^2 + r.branch(:, QF)^2); At = sqrt(r.branch(:, PT)^2 + r.branch(:, QT)^2); flow = (Af + At)/2; loading = flow ./ r.branch(:, RATE_A); The total active power losses can be computed by simply adding the injections at each end of the branch. losses = r.branch(:, PF) + r.branch(:, PT); -- Ray Zimmerman Senior Research Associate 419A Warren Hall, Cornell University, Ithaca, NY 14853 phone: (607) 255-9645 On Oct 1, 2012, at 12:43 PM, Evangelos Galinas <vagelisgali...@msn.com> wrote: > Hallo Basem, > > I guess, except if it's already somewhere else calculated, you can just grab > the abs(mpc.branch(:,14)) (power injected at one end)and divide by the > mpc.branch(:,6) (rating A). I > > Fot the losses just calculate the current and multiply it by the losses and > save it at some vector > > cheers > Date: Mon, 1 Oct 2012 18:33:33 +0200 > From: basem.id...@iwes.fraunhofer.de > To: matpowe...@cornell.edu > Subject: Line loading > > Hi all, > > I am a beginner user of Matpower, and I would like to know how I can > calculate the loding of a branch (e.g. in percentage). I also need to know > how I can save the losses of the branches in a matrix. > > Thanks in advance for any answer, > Basem Idlbi > > > > Basem Idlbi > Division Systems Engineering and Distribution Grids > Fraunhofer Institute for Wind Energy and Energy System Technology, IWES > Königstor 59 | 34119 Kassel / Germany > Phone +49 561 7294-166 | Fax +49 561 7294-200 >
