At 06:33 PM 6/21/99 -0500, Willmore, David wrote:
>Ahhh, because the smallest factor must be <= the sqrt() of the number!
Yes, but that doesn't matter here. We are checking for divisors less than some
relatively small limit (much smaller than the number itself). For a given
limit, there are fewer possible divisors as p increases.
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| Jud "program first and think later" McCranie |
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