At 07:39 PM 6/21/99 -0400, lrwiman wrote:
>Actually, it 2*k*p+1 must be ==+/-1 mod 8 which is 2/8=1/4. This can be
>further reduced by checking for divisibility by 3, and 5.
>So thats 1/(15*p) of numbers that we are actually checking.
Yes, but the crucial thing in answering his question is the factor of p.
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| Jud "program first and think later" McCranie |
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