> But (assuming n is composite) no prime factor of n can be greater than > n^0.5. So how can n^0.6065 be the average? > > (I hope I'm not showing my idiocy here! :) No, that's not correct. If n is composite, then it *must have* a prime factor <n^.5, but it can (though not always) have one larger e.g. 217=7*31 sqrt(217)~=14.73>7, but 31>14.73. -Lucas Wiman _________________________________________________________________ Unsubscribe & list info -- http://www.scruz.net/~luke/signup.htm Mersenne Prime FAQ -- http://www.tasam.com/~lrwiman/FAQ-mers
- Mersenne: Size of largest prime factor Pierre Abbat
- Re: Mersenne: Size of largest prime factor Jud McCranie
- RE: Mersenne: Size of largest prime factor Kyle Evans
- RE: Mersenne: Size of largest prime factor Kyle Evans
- RE: Mersenne: Size of largest prime factor Lucas Wiman
- RE: Mersenne: Size of largest prime factor Jud McCranie
- Re: Mersenne: Size of largest prime factor Paul Landon
- Re: Mersenne: Size of largest prime factor Jud McCranie
- Re: Mersenne: Size of largest prime factor Brian J. Beesley
- Re: Mersenne: Size of largest prime factor Henrik Olsen
- Re: Mersenne: Size of largest prime factor Paul Landon
