At 04:51 PM 1/23/00 -0600, Kyle Evans wrote:
>But (assuming n is composite) no prime factor of n can be greater than
>n^0.5. So how can n^0.6065 be the average?
I'm not assuming that n is composite. Some of them are prime, and in that
case the largest prime number is the number itself, and that brings up the
average.
+--------------------------------------------------------+
| Jud McCranie |
| |
| 137*2^197783+1 is prime! (59,541 digits, 11/11/99) |
| 137*2^224879+1 is prime! (67,687 digits, 1/00) |
+--------------------------------------------------------+
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