On Sat, 25 Apr 2020 00:49:41 -0700 (PDT), "'Alexander van der Vekens' via Metamath" <[email protected]> wrote: > I propose to use (the new version of) frlmgsum in step 85 and to replace > step 84 by ...
That fixes it! Thanks. I repaired the $d provisos, cleaned up the comments, and created a pull request to add the proof of aacllem to set.mm: https://github.com/metamath/set.mm/pull/1608 This is a complex proof of a simply-stated result, and I hate to see it lost. I suspect it will be used later, but that can only happen if we have it in the first place. --- David A. Wheeler -- You received this message because you are subscribed to the Google Groups "Metamath" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/metamath/E1jSLlx-0006PI-Oq%40rmmprod06.runbox.
