Such issues highlight that natural language contains many pitfalls when it 
comes to precision.
Technically, when you say "Any theorem of logic is necessary", I would 
interpret that as (⊢p) ⇒ □(⊢p). But you mean to say (⊢p) ⇒ (⊢□p).

Already the term "necessary" is questionable, as modal logic is about whether 
something is "necessarily true", which is not the same as "necessary" (the 
latter is less specific and can refer to things that are not about truth).

A more natural way to express that "□p" is a theorem in GL is to say that the 
statement that p is PA-provable is GL-provable. Which circumvents an issue that 
emerges only due to mixing meta with object language in natural language..

I only meant to point out some mistakes in terminology, it is up to you what 
you make of it!

________________________________
Von: [email protected] <[email protected]> im Auftrag von 
savask <[email protected]>
Gesendet: Montag, 1. Dezember 2025 14:01:03
An: Metamath
Betreff: [Metamath] Re: Advent of Metamath 2025

Thank you for the remarks. Admittedly, I haven't tried to be very precise in 
theorem comments, for the most part their goal is to provide at least some 
intuition for the symbols. I'll wait for a bit in case others (or you) have 
other remarks, so I'll update the file all in one go.

> But that is false. The necessitation rule actually says: if something (to be 
> true) is a theorem (i.e. provable from only axioms, no premises), then it to 
> be necessary (necessarily true) is also a theorem.

I'm a bit reluctant to use "provable" here as the box symbol is later 
interpreted as "provable in PA". I can rephrase the comment as follows "Any 
theorem of logic is necessary", this is the motivation used by Standford's 
encyclopedia of philosophy<https://plato.stanford.edu/entries/logic-modal/>.

> "Turns out this axiom is true in GL, hence GL extends K4." should probably 
> read "valid" rather than "true".

Again, to avoid loaded terms, I can rephrase it as "Turns out this axiom holds 
in GL ...". Is that okay?

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