Hi -
> From: Bernhard Praschinger <[EMAIL PROTECTED]>
>
> Audio: ( Samplerate * Channels * Bitsize ) / (8 * 1024)
> Video: (width * height * framerate * quality ) / (200 * 1024)
>
> You have to add both values together. To get the datarate in kb/sec.
Darn - I forgot that 'quality' is not a 0 thru 1.0 number but is
scaled by 100.
Too many different ranges/scales :)
(640 * 480 * 29.97 * 100) / (200 * 1024) gives 4495 or about 4495 * 8
kbits/sec (~35900kbits/sec). About half again as much as DV.
With audio at ~1500kbits/sec (187 kbytes/sec) a total rate would be
around 4680 or so. That's
4680 kbytes/sec is a long ways from 10 or 11Megabytes/sec. I was
curious if 'raid-0' was strictly necessary for capturing. With
rates in the ~4-5 megabyte/sec range it would seem that thruput isn't
the primary reason for a raid-0 setup. Quite useful for catenating
drives together into a bigger filesystem though ;)
Cheers,
Steven Schultz
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