Eric Wilhelm <[EMAIL PROTECTED]> writes: > my $date = today + 3*years + 3*months + 3*days; > Careful, that may not be the same as 'today + 3*days + 3*months + > 3*years'.
Yikes! > The caveat may apply if today is any day >= 28 -- if we run > out of days in the destination month, we stop at the end. I'd say that January 30 + 1 month should be March 1, not February 29. -- Johan
