You have to rebuild a brand new tuple, since the input field number 2 is the
output field number 1, and so on. The simplest, in my opinion, is to get
the fields in a list, and rebuild a tuple from the tail of that list.
%% return tuple T without its first field, and its remaining fields
%% moved one position "to the left"
fun {Foo T}
{List.toTuple {Label T} {Record.toList T}.2}
end
Cheers,
raph
On Fri, Oct 3, 2008 at 6:44 AM, Chris Rathman <[EMAIL PROTECTED]>wrote:
> What I want is take a record that has implicit indexes such as:
>
> a(10 20 30 40)
>
> and return a record with one less arity, stripping off the first value:
>
> a(20 30 40)
>
> I can get close with:
>
> {Record.filterInd a(10 20 30 40) fun {$ I X} I > 1 end}
>
> But that returns the value of
>
> a(2:20 3:30 4:40)
>
> which is not quite the same thing.
>
> Is there a way to do what I am trying to do?
>
> Thanks,
> Chris
>
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