Thanks. That did the trick. Not sure it is an efficient solution, but
if I was worried about efficiency, then I should be using lists anyway.
Thanks,
Chris
Raphael Collet wrote:
You have to rebuild a brand new tuple, since the input field number 2
is the output field number 1, and so on. The simplest, in my opinion,
is to get the fields in a list, and rebuild a tuple from the tail of
that list.
%% return tuple T without its first field, and its remaining fields
%% moved one position "to the left"
fun {Foo T}
{List.toTuple {Label T} {Record.toList T}.2}
end
Cheers,
raph
On Fri, Oct 3, 2008 at 6:44 AM, Chris Rathman <[EMAIL PROTECTED]
<mailto:[EMAIL PROTECTED]>> wrote:
What I want is take a record that has implicit indexes such as:
a(10 20 30 40)
and return a record with one less arity, stripping off the first
value:
a(20 30 40)
I can get close with:
{Record.filterInd a(10 20 30 40) fun {$ I X} I > 1 end}
But that returns the value of
a(2:20 3:30 4:40)
which is not quite the same thing.
Is there a way to do what I am trying to do?
Thanks,
Chris
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