michael lefevre wrote:

>In article <a7lmrm$[EMAIL PROTECTED]>, Bamm Gabriana wrote:
>
>>It is.
>>
>>Let a = 1.
>>a^2 = a (multiply both sides by a)
>>a^2 - 1 = a - 1 (subtract 1 from both sides)
>>(a + 1)(a - 1) = (a - 1) (factor it)
>>
>
>ok.
>
>>(a + 1) = 1 (cancel common factors)
>>
>
>whoops... a-1 is 0, so you've just divided both sides of your equation by
>zero!  that doesn't leave you with (a+1)=1...
>
>>QED/ :)
>>
>
>i'm afraid not :)
>
Good work! Although you shouldn't have given the answer
so early. :)



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