Sören Kuklau wrote: > On 3/25/2002 12:13 AM, Bamm Gabriana apparently wrote exactly the > following: > >>> That's like declaring that 1=2. >> >> >> >> It is. >> >> Let a=b. >> a^2 = a (multiply both sides by a) > > > That's only true for a=1 or a=0. > >> a^2 - 1 = a - 1 (subtract 1 from both sides) > > > Same as above. > >> (a + 1)(a - 1) = (a - 1) (factor it) >> (a + 1) = 1 (cancel common factors)
If a is one as you said in the other post, (a-1) is zero and thus you'll be dividing the expression by zero which is not allowed. See link in my other post for more info. >> 1 + 1 = 1 (substitution.) > > > Hmm, why is a=1 now? You said a=b. > > (a + 1) = 1 > a + 1 = 1 > a = 0 (minus one) >
