On Jan 3, 5:58 pm, "Jason Martin" <jason.worth.mar...@gmail.com>
wrote:
> Excellent!! Thanks for the error checking Michael!!
>
> Jason Worth Martin
> Asst. Professor of Mathematicshttp://www.math.jmu.edu/~martin
Ok, I have now verified that for all a up to 10**10 "(-
a^3).is_perfect_power()" returns true. Now obviously I should
implement my own version of some algorithm to check that a is a
perfect power and compare the cases where b up to some bound isn't.
But I doubt I will get to that any time soon.
Cheers,
Michael
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