>My protocol is delay insensitive. You can't make a delay insensitive
>protocol and use timeouts at the same time.
You can, just set the timeout to, well, 3 minutes (255 interrupts). That
will always be ok, because even the slowest MSX can transmit a byte in 3
seconds...
>Actually flipping both D0 and D1 (happens only as transmission error) is
>what causes the protocol to hang in the first place.
>
>I can ofcourse make my protocol partially delay insensitive. But there is
>another problem: performance. If I put a timeout counter in the inner loop,
>the speed will suffer a lot. So now I'm thinking about using the interrupt
>to generate timeouts.
That's true, although if you put it on the interrupt it won't take that
mucht time.
~Grauw
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