Zitat von [EMAIL PROTECTED]: > One reason may be due to your ON condition. > > ON table2.ID=table2.ID_table1 > > You reference table 2 twice and I doubt that on the table2 table id equals > id_table1 very often. Because table2 is LEFT JOINed to table1, you will > only be able to update the rows that match your ON condition. Again, that > would mean that you have nothing to update which would cause no changes to > table2 so it would appear that the IF() is always false.
Hmm, I really should have read that query twice, sorry UPDATE table1 INNER JOIN table2 ON table2.ID_table1=table1.ID SET table2.value=table2.value-IF(table1.condition=7,1,0), table1.condition=8 WHERE table1.ID=$id Problem: table2.value is never changed, even if table1.condition equals 7 before the query. Greetings Kai -- This signature is left as an exercise for the reader. -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]