with no comma (sorry): select sum(a.attendhours), s.attendhours from attendance a, attsum s where a.siteid = s.siteid and a.assignmentid = s.assignmentid and a.attenddate = s.attenddate and a.siteid = 'XXX' and a.attenddate >= 'XXXX-XX-XX' group by a.assignmentid, a.attenddate having sum(a.attendhours) != s.attendhours; <-- here is the end of the query
Mathias Selon [EMAIL PROTECTED]: > hi, > you can add > ... > ... > group by > a.assignmentid, > a.attenddate; > having sum(a.attendhours) != s.attendhours > > Mathias > > Selon Scott Pippin <[EMAIL PROTECTED]>: > > > I have the following query. > > > > select > > sum(a.attendhours), > > s.attendhours > > from > > attendance a, > > attsum s > > where > > a.siteid = s.siteid and > > a.assignmentid = s.assignmentid and > > a.attenddate = s.attenddate and > > a.siteid = 'XXX' and > > a.attenddate >= 'XXXX-XX-XX' > > group by > > a.assignmentid, > > a.attenddate; > > > > I want it to return those values where sum(a.attendhours) does not equal > > s.attendhours. What more do I need to add to my query to accomplish this? > > > > Thanks in Advance > > > > Scott Pippin > > [EMAIL PROTECTED] > > > > > > > > -- > MySQL General Mailing List > For list archives: http://lists.mysql.com/mysql > To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] > > -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
