2006/9/5, Ben Lachman <[EMAIL PROTECTED]>:
So possibly a better solution would be to create a temporary table and then do a subquery on that table?
yes. Or do a : SELECT id FROM t1 WHERE name LIKE '%s1%' OR name LIKE %'s2%' OR name LIKE '%s3%' but depending on your data, a table may be the way to go.
->Ben On Sep 4, 2006, at 7:37 AM, Visolve DB Team wrote: > Hi > > The ANY keyword, which must follow a comparison operator, means > "return TRUE if the comparison is TRUE for ANY of the values in the > column that the subquery returns > > In has 2 forms: > 1. IN (subquery). [The word IN is an alias for = ANY (subquery)]. > 2. IN (list of values seperated by comma) > > Hence the exact syntax to use is: > Select <fields> from < table> where <fieldname> = ANY ( select > <fieldname> from <table>); > > Ref: http://dev.mysql.com/doc/refman/5.0/en/any-in-some- > subqueries.html > > Thanks > ViSolve DB Team > > ----- Original Message ----- > From: "Ben Lachman" <[EMAIL PROTECTED]> > To: <mysql@lists.mysql.com> > Sent: Sunday, September 03, 2006 10:33 AM > Subject: IN & ANY subqueries > > >> I have a string comparison that I would like to do against a short >> list of constant strings. >> >> at the moment I am using the syntax >> >> SELECT id FROM t1 WHERE name IN('s1', 's2', 's3', ...); >> >> However, this limits me to exact matches and I'd like to move to a >> caparison expersion that lets me match names that contain any of the >> list. The MySQL docs state that 'IN()' is an alias to '= ANY()' >> however when I substitute' = ANY' for IN I get a parse error. What >> I'd like to do is write something like (although I figure there may >> be a better way to do the comparison that I am not thinking of): >> >> SELECT id FROM t1 WHERE name LIKE ANY('%s1%', '%s2%', '%s3%', ...); >> >> Does anyone know a way to do this? >> >> Thanks, >> >> ->Ben >> -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
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