Hello I've tried the following with mysql 4.1.11
SELECT * FROM quick_contact WHERE (`status` = '0') OR (`status` = '2'
AND `update` < '".(time()-864000)."') CASE WHEN `update` = '' THEN ORDER
BY `date` DESC ELSE ORDER BY `update` DESC END CASE;
It does not work but, is it my code that is wrong or is it just that
case does not work with mysql 4.1.11 ?
Thanks :)
Kristian Myllymäki a écrit :
mysql version?
http://dev.mysql.com/doc/refman/5.0/en/case-statement.html
order by case when updated is not null then updated else created end desc;
/Kristian
On Tue, Apr 8, 2008 at 1:04 PM, Richard <[EMAIL PROTECTED]> wrote:
Hello,
I've got a table which containes two date colomns.
The first one is called `date` and the second `update`
In the first one I put the ticket creation date, and on update I add or
change the update value.
So the update colomn does not contain a value until the first update has
been done.
I would like to order the tickets by their last update value. And if this
value does not exist use the date value.
at the moment I use this :
ORDER BY `date` DESC"
and I would like to replace it by something like this :
ORDER (IF `update`!= '' BY UPDATE ELSE BY DATE)
I know this code is completly wrong, just to try and show you what I need
...
Here is an example of what I want to achieve
num | date | update
-------------------------------------------
1 | 1 |
2 | 10 | 60
3 | 20 |
4 | 30 |
5 | 40 | 90
6 | 50 |
The required result would be :
num | date | update
-------------------------------------------
5 | 40 | 90
2 | 10 | 60
6 | 50 |
4 | 30 |
3 | 20 |
1 | 1 |
Thanks in advance :)
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