i.e. just try this: mysql> select 4E5664736F400E8B482EA7AA67853D13; ERROR 1367 (22007): Illegal double '4E5664736' value found during parsing
-Hank On Mon, Dec 20, 2010 at 12:50 PM, Hank <hes...@gmail.com> wrote: > > Here's my 5 second guess.. > > 4E5664736... is being interpreted as a number in scientific notation .. > i.e. 4*10^5664736 and the parser doesn't like that as a field name. > > -Hank > > > On Mon, Dec 20, 2010 at 12:43 PM, Ramsey, Robert L < > robert-ram...@uiowa.edu> wrote: > >> I am having the hardest time getting a select as statement right. Here is >> the full query: >> >> select >> SUM(IF(image='EE0840D00E2ED8A317E5FA9899C48C19',1,0)) as >> EE0840D00E2ED8A317E5FA9899C48C19, >> SUM(IF(image='235C7987796D5B7CEBF56FBDA2BF7815',1,0)) as >> 235C7987796D5B7CEBF56FBDA2BF7815, >> SUM(IF(image='96DC0562ED6E6F7FE789A18E09BC5889',1,0)) as >> 96DC0562ED6E6F7FE789A18E09BC5889, >> SUM(IF(image='D8B0EA710D2EF408391132F451AE724A',1,0)) as >> D8B0EA710D2EF408391132F451AE724A, >> SUM(IF(image='018C4DB7229D7D2BEB040D241739B784',1,0)) as >> 018C4DB7229D7D2BEB040D241739B784, >> SUM(IF(image='98DE1FCA50AC9CE6E0FEA25BAB0177FE',1,0)) as >> 98DE1FCA50AC9CE6E0FEA25BAB0177FE, >> SUM(IF(image='4E5664736F400E8B482EA7AA67853D13',1,0)) as >> 4E5664736F400E8B482EA7AA67853D13, <--offending line >> SUM(IF(image='FEB810A43A1B275605BD6B69F444700C',1,0)) as >> FEB810A43A1B275605BD6B69F444700C >> from dsrssfeed >> >> If I remove that one line, the query works fine. If I do: >> >> select SUM(IF(image='4E5664736F400E8B482EA7AA67853D13',1,0)) as 4E from >> dsrssfeed ; >> >> it works. But these fail: >> >> select SUM(IF(image='4E5664736F400E8B482EA7AA67853D13',1,0)) as >> 4E5664736F400E8B482EA7AA67853D13 from dsrssfeed ; >> select SUM(IF(image='4E5664736F400E8B482EA7AA67853D13',1,0)) as 4E5 from >> dsrssfeed ; >> >> It can't be field name length, since even 4E5 fails, the field name can >> start with a number since 4E succeeds. >> >> Any ideas? >> >> The goal is to see what arbitrary images have information associated with >> them. The table has two fields: image is a UID that is the primary key, >> and caption which is a varchar(255) that has information about the image. >> Images are added and deleted from the table as they are changed on a web >> page. The UID is generated by a third party program that I have to >> interface with and have no control over. An array of image UIDs is sent to >> the php script and the script needs to determine which UIDs are present in >> the table. Rather than make N number of individual queries as I iterate >> through the array, I iterate through the array and build the query on the >> fly to make one query. Then I iterate through the array again and check the >> value in the field. 1 means the UID has an entry, 0 means it doesn't. I >> thought doing 1 mysql call would be more efficient than lots of calls as I >> iterate through the array. But since there will probably never be more than >> 100 images in the table at any one time, it may not make any difference. >> But now I'm just curious as to why this is happening. >> >> Thanks, >> >> Bob >> >> >> >> >> >
