Thanks, but how can I pass the current users value from the other query ? On Thu, Feb 3, 2011 at 4:22 PM, Simcha Younger <sim...@syounger.com> wrote:
> On Thu, 3 Feb 2011 13:55:36 +0000 > Tompkins Neil <neil.tompk...@googlemail.com> wrote: > > > SELECT DISTINCT(away_teams_id) AS teams_id > > FROM fixtures_results > > WHERE (fixtures_results.away_users_id = *users.users_id*) > > > Any ideas why I'm getting Unknown column 'users.users_id' in 'where > clause' > > for the part of the statement that I've marked as *bold* and how I can > over > > come this problem ? > > You have to add the users table to the subquery. > Your subquery only has the fixtures_results table in the 'from' clause, and > the subquery is not aware of the tables you use in the outer query. > > -- > Simcha Younger <sim...@syounger.com> > > -- > MySQL General Mailing List > For list archives: http://lists.mysql.com/mysql > To unsubscribe: > http://lists.mysql.com/mysql?unsub=neil.tompk...@googlemail.com > >
