>>>> 2012/04/04 19:56 +0200, joe j >>>>
/*STEP 2. from the dos prompt?*/
for x in UK ZA IN CN;
do mysql -ujoe -p -e "INSERT INTO `table_new`
SELECT var1, var2`, (case when (country='${x}') then 1 else 0 end) AS citizen
,'${x}' AS ctry
FROM `'${x}'_table`
LEFT JOIN
WORLD
USING(YEAR)";
For some reasons step2 is not working.
I assume step 2 must be run from DOS prompt (my mysql runs on a
server, and I am using PuTTY). Any thoughts?
<<<<<<<<
I yet suggest that you write an SQL procedure with a constructed string passed
to PREPARE. You need a table with all the countries, and a cursor in the
procedure to scan the table--or you could use a string and step through two
characters at a time. It would be more complicated than that bit of
shell-programming, but independent of your OS.
A loop with a character string somewhat thus runs:
DECLARE i INT DEFAULT 1;
WHILE i < 8 DO
PREPARE ... SUBSTRING('UKZAINCN', i, 2) ....
....
SET i = i + 2;
END WHILE;
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