That means either your $result doesn't exist or the query you used to get
$result failed.
Use something like this (at least in PHP) to see what MySQL's error was:
if ($result=mysql_query($query))
{
//worked
//echo mysql_num_rows($result);
}
else
{
//didn't work
$errMsg="Failed Query: $customer_select<br>".mysql_errno()." :
".mysql_error();
echo $errMsg; echo "<P>";
}
Ryan Shrout
-----Original Message-----
From: Felicia [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, June 20, 2001 9:29 AM
To: mysql post
Subject: mysql/php
I am trying to use php to print my results. This is my code (I have checked
to see if fields are correct with regards to spelling and so on):
printf("Genus: %s<br>\n", mysql_result($result,0,"genus"));
and I get the error message:
Warning: Supplied argument is not a valid MySQL result resource in
/home/sites/site197/web/practice/phpmysqlpract.php on line 26
Genus:
Can you tell me what I am doing wrong?
"The last of the human freedoms is to choose one's attitudes."
-Victor Frankl
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