SELECT id FROM mytable WHERE type IN(x,y,z) GROUP BY id; On 22 November 2012 15:01, Neil Tompkins <neil.tompk...@googlemail.com> wrote: > Michael, > > Thanks this kind of works if I'm checking two types. But what about if I > have 5 types ? > > On Thu, Nov 22, 2012 at 2:53 PM, Michael Dykman <mdyk...@gmail.com> wrote: > >> response did not go to the list.. >> >> >> I assume that you mean the id must be associated with both type=5 AND >> type=2 as opposed to type=5 OR type=2; >> >> in some dialect of SQL (not mysql) you can do this: >> select distinct id from 'table' where type=5 >> intersect >> select distinct id from 'table' where type=2 >> >> >> As INTERSECT is not avilable under mysql, we will have to go the JOIN route >> >> select distinct a.id from mytable a >> inner join mytable b on (a.id=b.id) >> where a.type= 2 and b.type = 5; >> >> - michael dykman >> >> On Thu, Nov 22, 2012 at 9:30 AM, Neil Tompkins >> <neil.tompk...@googlemail.com> wrote: >> > Hi, >> > >> > I'm struggling with what I think is a basic select but can't think how to >> > do it : My data is >> > >> > id,type >> > >> > 1000,5 >> > 1001,5 >> > 1002,2 >> > 1001,2 >> > 1003,2 >> > 1005,2 >> > 1006,1 >> > >> > From this I what to get a distinct list of id where the type equals 2 >> and 5 >> > >> > Any ideas ? >> > >> > Neil >> >> >> >> -- >> - michael dykman >> - mdyk...@gmail.com >> >> May the Source be with you. >> >> >> -- >> - michael dykman >> - mdyk...@gmail.com >> >> May the Source be with you. >> >> -- >> MySQL General Mailing List >> For list archives: http://lists.mysql.com/mysql >> To unsubscribe: http://lists.mysql.com/mysql >> >>
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