>
> Incredibly difficult.
>
> select foo,count(*) as cnt from da_table group by foo having cnt >1;
>
ahh, I'd be slapping my forehead right now, except I've never used "having"
Thanks for helping out. :)
Stephen
---------------------------------------------------------------------
Before posting, please check:
http://www.mysql.com/manual.php (the manual)
http://lists.mysql.com/ (the list archive)
To request this thread, e-mail <[EMAIL PROTECTED]>
To unsubscribe, e-mail <[EMAIL PROTECTED]>
Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
