Thanks for the help. Got that to work no problem.
Mike
----- Original Message -----
From: "Harrison C. Fisk" <[EMAIL PROTECTED]>
To: "Mike" <[EMAIL PROTECTED]>
Cc: "mysql list" <[EMAIL PROTECTED]>
Sent: Thursday, June 13, 2002 5:48 PM
Subject: Re: Need Help with JOIN
> Mike,
>
> With the way you have it written below, all of the pic1_id, pic2_id,
> pic3_id, and pic4_id must be equal (because they all equal pic.pic_id).
> Since this wasn't true for any of the rows, that is why you were
> getting no results.
> To get each picture value seperately, you will have to do one join for
> each pic#_id, which will give you something like:
>
> SELECT *
> FROM pics AS p1, pics AS p2, pics AS p3, pics AS p4 , outings AS o
> WHERE o.pic1_id=p1.pic_id
> AND o.pic2_id=p2.pic_id
> AND o.pic3_id=p3.pic_id
> AND o.pic4_id=p4.pic_id;
>
> Or as you had it written before using INNER JOIN's:
>
> SELECT *
> FROM outings as o INNER JOIN pics AS p1 ON o.pic1_id=p1.pic_id
> INNER JOIN pics AS p2 ON o.pic2_id=p2.pic_id
> INNER JOIN pics AS p3 ON o.pic3_id=p3.pic_id
> INNER JOIN pics AS p4 ON o.pic4_id=p4.pic_id;
>
> Either of those should work fairly well. Hope that helps some.
>
> Harrison
>
>
> Mike wrote:
>
> >Hello,
> >
> >I have 2 tables(pics and outings)
> >
> >pics
> >pic_id, tinyint
> >path, varchar
> >
> >outings
> >outings_id, tinyint
> >pic1_id, tinyint
> >pic2_id, tinyint
> >pic3_id, tinyint
> >pic4_id, tinyint
> >
> >When i try to do a join like this
> >
> >mysql_query("SELECT * FROM pics inner join outings on
> >outings.pic1_id=pic.pic_id and outings.pic2_id=pic.pic_id and
> >outings.pic3_id=pic.pic_id",$db) or die(mysql_error());
> >
> >Nothing is returned. The query runs ok(nothing from mysql_error). When I
> >drop outings.pic2_id=pic.pic_id and outings.pic3_id=pic.pic_id from the
> >query works and returns the path of the pic.
> >
> >I'm fairly certain that the above returns nothing because of the multiple
> >pic.pic_id's in the query. But I don't know what to do get it
> >working(Redesign? or Is there something I could change in the query?)
> >
> >Thanks in advance for any help,
> >Mike
> >sql,mysql
> >
> >
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