Kittiphum,
Wednesday, December 04, 2002, 1:49:08 PM, you wrote:
K> This query can find the record in Table1 that not found in Table2
K> SELECT Table1.ID FROM Table1 LEFT JOIN Table2 Using(ID)
K> WHERE Table2.ID IS NULL
K> and what query that use to delete the record in Table1 that not found
K> in Table2 such as
K> Delete from Table1 where Table1.ID in
K> SELECT Table1.ID FROM Table1 LEFT JOIN Table2 Using(ID)
K> WHERE Table2.ID IS NULL
K> because of MySQL ver 3.23.XX not support sub select while we still
K> use 3.23.XX
In 3.23. you can't do it with single SQL statement. You can use
programming language or use CONCAT() function as described here:
http://www.mysql.com/doc/en/ANSI_diff_Sub-selects.html
K> and one more question
K> How to merge table with varchar type not char type (because if table
K> contain varchar column we can't merge them but with table that only
K> have char column it work)
It works fine for me. If it doesn't work for you, please, provide some more info.
--
For technical support contracts, goto https://order.mysql.com/?ref=ensita
This email is sponsored by Ensita.net http://www.ensita.net/
__ ___ ___ ____ __
/ |/ /_ __/ __/ __ \/ / Victoria Reznichenko
/ /|_/ / // /\ \/ /_/ / /__ [EMAIL PROTECTED]
/_/ /_/\_, /___/\___\_\___/ MySQL AB / Ensita.net
<___/ www.mysql.com
---------------------------------------------------------------------
Before posting, please check:
http://www.mysql.com/manual.php (the manual)
http://lists.mysql.com/ (the list archive)
To request this thread, e-mail <[EMAIL PROTECTED]>
To unsubscribe, e-mail <[EMAIL PROTECTED]>
Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php