Hi again, After some struggling, I have managed to get the problem below 99% working, the problem now is that I can't get them in descending order. Here is my select statement.
$query = "select manager.name, position, MAX(goals) from roster join reference join manager where manager.idn=reference.idn and reference.idp=roster.idp and position like 'F' GROUP BY manager.name order by goals desc"; Using the example below, this is what I get: Bill 70 John 48 Fred 87 This is what I want: Fred 87 Bill 70 John 48 TIA ----- Original Message ----- From: "C. Reeve" <[EMAIL PROTECTED]> To: "MySQL List" <[EMAIL PROTECTED]> Sent: Friday, February 07, 2003 1:57 PM Subject: Select question > Hi, > > I have a database with 3 names in it. In each of these names is 5 > categories that have numbers in them. I want to be able to do a select and > get the top number from each category for each name and display them from > most to least. I have checked all the docs on the select statement, but > this is escaping me at the moment. > > TIA > > i.e > > This is what is in the database. > > Bill 36 20 50 46 70 > John 26 30 32 48 46 > Fred 87 40 19 62 42 > > This is what I want to be able to show: > > Fred 87 > Bill 70 > John 48 > > > SPAM bypass: sql, query, queries, smallint > --------------------------------------------------------------------- Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail <[EMAIL PROTECTED]> To unsubscribe, e-mail <[EMAIL PROTECTED]> Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
