On 2 Dec 2003 at 7:20, Greg Jones wrote: <snip> > > select l.ltsysid,l.lientraknum, c.name from lientrak as l, customer as c > where l.custsysid=c.custsysid > and l.ltsysid in (select l2.ltsysid from lientrak as l2 where l2.lientraknum > like '2003-%') > <snip> >
Hi greg Yopur problem is that you are using a subquery - MySQL 4.0.1.5 does not support subqueries - you will need 4.1 for that... A possible workaround (based on your query above - so please tolerate any mistakes :) ) : select l.ltsysid,l.lientraknum, c.name from lientrak as l, customer as c where l.custsysid=c.custsysid and l.lientraknum like '2003-%' Actually, having written the above workaround, I am puzzled as to why you would need the subquery at all :)...unless of course, above workaround is completely wrong, and I have to eat humble pie ....again..... Rory McKinley Nebula Solutions +27 82 857 2391 [EMAIL PROTECTED] "There are 10 kinds of people in this world, those who understand binary and those who don't" (Unknown)
