On Thu, Feb 26, 2004 at 09:50:39AM -0700, Sasha Pachev wrote: > If I understood the problem correctly, the answer to it is actually > undefined. If you order by lastPostTime, the records with the same > lastPostTime value can be returned in any order. > > I guess to accomplish your goal you could add a column seq_ord int > not null to keep track of the record order according to your > expectations, and then order by lastPostTime,seq_ord
The table has an "id" column ("id" is the primary key) that works like your seq_ord suggestion, so I guess I could have a query like this: SELECT * FROM topics ORDER BY lastPostTime DESC, id DESC But then given a certain id = $id, I'm not sure of the best way to count the number of rows that would be returned in the above query before the row with id = $id. Is there any solution that looks like this: SELECT COUNT(*) FROM topics ORDER BY lastPostTime DESC, id DESC HAVING <<not sure what to put here?>> Or do I have to do this, which feels kludgy: $postTime = SELECT lastPostTime FROM topics WHERE id = $id; SELECT COUNT(*) FROM topics WHERE lastPostTime > $postTime OR (lastPostTime = $postTime AND id > $id); -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]