Barry Smith writes:
>i have 2 tables one pet containing petName and petType other table is color 
>containgin petName and petColor. The code which i keep getting errors on is:
>
>Select * from pet outer join color using (pet.petName=petcolor.petName) ;

Unfortunately petcolor is not a table.  Based upon your prior information
I think you are looking for:

Select * from pet left join color on pet.petName=color.petName;

Brad Eacker ([EMAIL PROTECTED])



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