On 4/8/04 1:05 PM, "Michael Stassen" <[EMAIL PROTECTED]> wrote:
> > James McConnell wrote: > >> On 4/8/04 9:18 AM, "Barry ." <[EMAIL PROTECTED]> wrote: >> >> >>> Hi >>> >>> I recently began to work through the Book entitled PHP & MySQL For Dummies >>> and i am currently stuck towards the end of the forth chapter ive done >>> everything as said so in the book but i keep getting an error message. Here >>> is an outline of the problem: >>> >>> i have 2 tables one pet containing petName and petType other table is color >>> containgin petName and petColor. The code which i keep getting errors on is: >>> >>> Select * from pet outer join color using (pet.petName=petcolor.petName) ; >>> >>> Now Ive posted my problem on several forums on the internet and have a wide >>> range to replys suggesting what to do but nothing seems to work. >>> >>> Can anyone please help me?? >>> >>> Barry Smith >> >> I think the reason that's not working is because that doesn't look like >> MySQL syntax for a join statement. From the MySQL documentation, try this: >> >> SELECT * FROM pet OUTER JOIN color ON pet.petName=petColor,petName; >> >> Keep in mind this will only return rows in pet that have corresponding rows >> in color. I hope that's what you're looking for. >> >> The above code is not tested, but that's the proper JOIN syntax in MySQL. >> Going through the documentation, I don't see a USING keyword anywhere. That >> looks suspiciously like Oracle code. >> >> Hope that help! > > USING is documented in the manual <http://www.mysql.com/doc/en/JOIN.html>. > USING expects a list of columns which exist in both tables. The following > are quivalent: > > SELECT * FROM pet JOIN color ON pet.petName = color.petName; > SELECT * FROM pet JOIN color USING (petName); > > Michael > Sorry, all! I just did a cursory glance at the docs, but I swear I never saw the USING statement before. /me feels like idiot James -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
