Thomas Nyman wrote:
Hi
I found an instruction on the net concerning "Date Arithmetic" and which seems to be exactly what I need to hel me get going..however there seems to be either a mistake on my behalf or on the writers behalf.
Can anyone say whats wrong with this query
$query2="UPDATE KK_Fatalie SET datum = DATE_ADD(date,INTERVAL intervall' ''.$typeArray[$row->type].")WHERE kk_ID="".$row->kk_ID"";
The query is suppose to result in the following;
do an UPDATE on table KK_Fatalie and set the column datum equal to todays date increased with the interval stated in the column intervall where the kolumn kk_ID equals the kk_ID in my earlier php query.
You say you want to add an interval to today's date, but your query is apparently adding to a column named date. To get today's date, use the CURDATE() function.
$query2="UPDATE KK_Fatalie
SET datum = CURDATE() + INTERVAL intervall ".$typeArray[$row->type]
." WHERE kk_ID="".$row->kk_ID"";I'm assuming inteval1 holds an integer and $typeArray[$row->type] holds an appropriate INTERVAL type (DAY or YEAR or...)
On the other hand, if you really do have a column named date you wish to use, then you need to realize that date is a reserved word, so it has to be enclosed in backticks to use it as a name.
Michael
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