You only need to specify from tabel on the first table. Like this. select cattbl.name as cat, dogtbl.name as dog, birdtbl.name as bird from dogtbl left join cattbl on cattbl.id=dogtbl.catid left join birdtbl on birdtbl.dogid=dogtbl.id;
-Eric On Mon, 5 Jul 2004 09:28:02 -0700, bruce <[EMAIL PROTECTED]> wrote: > my test tbls > > cattbl dogtbl birdtbl > name name name > id -------> catid ---> dogid > id ---- id > > so > dogtbl.catid = cattbl.id > birdtbl.dogid = dogtbl.id > > my question is how i can use "left joins" to produce the results set with the names > of all three cat/dog/bird... > > i've tried various derivatives of the following... > mysql> select cattbl.name as cat, > -> dogtbl.name as dog, birdtbl.name as bird > -> from dogtbl > -> left join cattbl on cattbl.id=dogtbl.catid > -> from birdtbl > -> left join dogtbl on birdtbl.dogid=dogtbl.id; > > i keep getting an error complaining about the 2nd "from/left join"... > > i know how to get the results using "where/and" logic... but i'm trying to get a > better feel of the "left join" process... > > after looking at mysql/google, i'm still missing something... > > any comments/criticisms appreciated.. > > thanks > > -bruce > > > -- > MySQL General Mailing List > For list archives: http://lists.mysql.com/mysql > To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] > > -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
