Mysql 4 SELECT c.campaign_name, count(*), c.id FROM addresses as a INNER JOIN addresses_incampaign as i on (a.email_address = i.email_address) INNER JOIN campaigns as c on (i.campaign_id = c.id) WHERE a.user_id = "1" AND i.user_id = "1" GROUP BY c.id ORDER BY c.id
This gives me FooNmae 100 BarName 250 FUD name 127 Within the addresses table is a field called status, it is a enum and can be 'optin' or 'optout'. I need to also show how many there are of each of those as well. I have looked at count(a.status) but that just returns the total numbers listed above, count(DISTINCT a.status='optin') gives me 2 for some reason. Suggestions? -- ------------------------------------------------------------- Scott Haneda Tel: 415.898.2602 http://www.newgeo.com Fax: 313.557.5052 [EMAIL PROTECTED] Novato, CA U.S.A. -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
