Hi again,
I have a question about the <include> task and the
project::get-buildfile-path() function.
I would like to know if there is a way to get the path of an included
build file, rather than the containing build file, from withing the
included file.
Example:
C:\folder\project.build
-----------------------
<project>
<include buildfile="..\include.build" />
</project>
C:\include.build
-----------------------
<project>
<echo message="${project::get-buildfile-path()}" />
</project>
In this case, the message display is "C:\folder\project.build", but, I
need to find a way to have a function return "C:\include.build".
Any suggestions?
Thanks,
Steve
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