Sorry , actually have to multiply the hrStorageUsed by the AllocationUnits,
i.e.
1172379 x 4096.
So actually almost all the Physical and Real memories are used!
But this is definitely not the case.
So how to get the total memory used on a Freebsd system from snmp?
thank you.
hrStorageIndex hrStorageType
hrStorageDescr hrStorageAllocationUnits hrStorageSize hrStorageUsed
hrStorageAllocation
Failures
1 HOST-RESOURCES-TYPES::hrStorageRam Physical
memory 4096 Bytes 128596 117279 0
2 HOST-RESOURCES-TYPES::hrStorageRam Real
memory 4096 Bytes 121008 103978 0
On Tue, Aug 12, 2008 at 2:21 AM, Dave Shield <[EMAIL PROTECTED]>wrote:
> 2008/8/12 Chee Meng Gui <[EMAIL PROTECTED]>:
> > So the hrStorageEntry.hrStorageUsed.1 is in kilobytes?
>
> hrStorageUsed is reported in the units specified in hrStorageUnits.
> So if hrStorageUnits.1 is 1024, then hrStorageUsed.1 is in Kb
>
>
> > When I checked this result against the used memory output of sysctl {
> > hw.physmem - ( ( vm.stats.vm.v_inactive_count + vm.stats.vm.v_cache_count
> +
> > vm.stats.vm.v_free_count ) * hw.pagesize ) } , the two were not equal.
>
> On FreeBSD with the latest (5.4.x) agent, "Physical memory" is
> retrieved by running sysctl on HW_USERMEM. Most of the other
> values are calculated by running sysctl on VM_METER
>
> See 'agent/mibgroup/hardware/memory/memory_freebsd.c'
> for the details.
>
> Dave
>
--
Chee Meng Gui
Function Engineering
650-833-0660
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