I left out params for clarity... I wasn't doing it right so i didn't want
to muddy up my example.
I agree, it's not very clear what my intentions are here...

On Mon, May 28, 2012 at 2:29 PM, Angel Java Lopez <ajlopez2...@gmail.com>wrote:

> Hmmm... I'm a bit confused.
>
> In your gist, you define lambda_good as
>
> function lambda_good() ... // no parameters
>
> but in your Ruby code, you define it explicitly with TWO arguments.
>
> What were your intention?
>
> On Mon, May 28, 2012 at 2:37 PM, Joshua Bowles <bowlesl...@gmail.com>wrote:
>
>> I'm clearly missing something about anonymous functions in node. As a
>> learning exercise I'm trying to pass multiple lambdas to a function.
>> I've got a gist https://gist.github.com/2820160  (and a comparison in
>> Ruby of what I'm trying to do https://gist.github.com/2820073).
>>
>> Thanks in advance!
>>
>> I can do this in node:
>>
>> function executeThree(someFunction, value) {
>>
>>   someFunction(value);
>>
>> }
>> executeThree(function(word) {console.log(word); }, "lambda_three");
>>
>>
>> I'm not able to figure out how to pass multiple anonymous functions to a
>> function such as this:
>>
>> function lambda_good( ) {
>>
>>   function executeOne(someFunction, someValue) {
>>
>>     someFunction(someValue);
>>
>>   }
>>
>>   function executeTwo(anotherFunction, anotherValue){
>>
>>     anotherFunction(anotherValue);
>>
>>   }
>> }
>>
>>
>>
>> I've toyed with a lot of different definitions for lambda_good but I
>> can't seem to get it to work. Can someone help me see what I'm missing here?
>>
>> SIDE NOTE: this is how I can do it Ruby;
>>
>> def func_one
>>
>>   func_one = lambda do
>>
>>     puts "lambda_one"
>>
>>   end
>>
>>
>>   #func_one.call
>> end
>> def func_two
>>
>>   func_two = lambda do
>>
>>     puts "lambda_two"
>>
>>   end
>>
>>
>>   #func_two.call
>> end
>>
>> def lambda_good(func1,func2)
>>
>>   func1.call
>>
>>   func2.call
>>
>> end
>>
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