If there really are only two functions that have the same callback
signature, then it's super easy taking advantage of named function
value hoisting.
if (cond) async1(onDone);
else async2(onDone);
function onDone(err, result) {
// the function finished
}
But I suspect the question involves more complicated cases in practice.
On Tue, Aug 7, 2012 at 9:44 PM, Andy <[email protected]> wrote:
> I would personally go with using promises.
>
> var q = require('q');
> q.ncall(function() {
> if(cond) {
> return async1(); // this is a promise
> }
> return async2(); // so is this
> }).then(function(res) {
> // hooray! one of them finished
> }).error(function(res) {
> // something went wrong!
> });
>
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