On Sun, 11 Jan 2004, Peter Münster wrote:
> %%%%%% Here is the problem: dividing one length by another. %%%%%%
Hello,
I've found a solution. Here is now the full environment:
% this environment works a little bit like \usepackage[DIVcalc]{typearea}
% in LaTeX as explained in detail in scrguien.pdf (KOMA-Script documentation)
\startenvironment e-test
\def\BCOR{3mm}% eventual binding correction
\setbox\scratchbox\hbox{\dorecurse{26}{\character\recurselevel}}
\newdimen\PageWidth
\PageWidth=\paperwidth
\doifmode{BCOR}{\PageWidth=\dimexpr(\PageWidth-\BCOR)}
\unprotect
\begingroup
\catcode`P=12
\catcode`T=12
[EMAIL PROTECTED]
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\def\rem@@pt##1.##2PT{##1}}}
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[EMAIL PROTECTED]@pt\the}
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[EMAIL PROTECTED](10\paperheight/[EMAIL PROTECTED](10\PageWidth))}
\protect
\newdimen\Width
\newdimen\Height
\newdimen\Back
\Width=\dimexpr(2.5\wd\scratchbox)
\Height=\dimexpr(\Ratio\Width)
\headerheight=2.75\baselineskip
\edef\Top{\the\dimexpr((\paperheight - \Height) / 3 - \headerheight)}
\doifmodeelse{oneside}{%
\Back=\dimexpr((\PageWidth - \Width) / 2)
}{%
\Back=\dimexpr((\PageWidth - \Width) / 3)
\setuppagenumbering[alternative=doublesided]}
\doifmode{BCOR}{\Back=\dimexpr(\Back + \BCOR)}
\Height=\dimexpr(\Height + \headerheight + \footerheight)
\setuplayout[header=\the\headerheight,height=\the\Height,
width=\the\Width,topspace=\Top,backspace=\the\Back]
\stopenvironment
Cheers, Peter
--
http://pmrb.free.fr/contact/
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