On Sun, 11 Jan 2004, Peter Münster wrote:
> %%%%%% Here is the problem: dividing one length by another. %%%%%%
[code skipped]
Some days ago Willy Egger sent me a translation/summary of this koma page size adventure.
Since I opt for a more contexty solution i want to follow a stepwise approach in getting this done. As a start:
(1) the ratio: this is the most efficient and (on average) accurate solution that also handles large paper sizes:
%edef\layoutratio{\withoutpt{\the\dimexpr(8\paperheight/\dimexpr(\paperwidth/ 8192))}}
%edef\layoutratio{\withoutpt{\the\dimexpr(4\paperheight/\dimexpr(\paperwidth/16384))}}
%edef\layoutratio{\withoutpt{\the\dimexpr(2\paperheight/\dimexpr(\paperwidth/32768))}}
\edef\layoutratio{\withoutpt{\the\dimexpr(2\paperheight/(\paperwidth/32768))}}
(2) for the moment this way, will be handled slightly different (because in context we can mix layouts and layouts can be dynamic
\def\layoutwidth
{10cm}\unprotected \def\layouthfheight
{\dimexpr(\layoutparameter\c!hoofd+\layoutparameter\c!hoofdafstand+
\layoutparameter\c!voet +\layoutparameter\c!voetafstand )}\def\layoutheight
{\dimexpr(\layoutratio\dimexpr(\layoutwidth)+\layouthfheight)}(3) this brings us:
\definelayout
[koma] % actually i want a better name since it's one of a set of calculations
[backspace=\dimexpr((\paperwidth-\layoutwidth)/2),
width=middle, % less rounding errors than \layoutwidth,
cutspace=\dimexpr((\paperwidth-\layoutwidth)/2),
header=2\lineheight,
headerdistance=\lineheight,
height=middle, % less rounding errors than \layoutheight
footerdistance=\lineheight,
footer=2\lineheight,
topspace=\dimexpr(1\dimexpr(\paperheight-(\layoutheight+\layouthfheight))/3),
bottomspace=\dimexpr(2\dimexpr(\paperheight-(\layoutheight+\layouthfheight))/3)]
\setuplayout [koma]
(4) the 'number of chars per line' .. i'll come back to that
Hans
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