Thanks Aditya!
I overlooked this change in mkiv…
Best regards: OK
On 21 oct. 2013, at 22:18, Aditya Mahajan <adit...@umich.edu> wrote:
> On Mon, 21 Oct 2013, Otared Kavian wrote:
>
>> Dear Hans,
>>
>> I noticed a difference between mkii and mkiv in the behavior of \mframed: it
>> seems that in mkiv the frame is not vertically aligned with the the + sign
>> in the following example (or rather it is not vertically centered, please
>> see the attached PDF produced with ConTeXt ver: 2013.10.15 13:52 MKIV).
>> Does one have to use now a new key to require this sort of alignment?
>>
>> Best regard: OK
>>
>> %%%% begin mframed-example.tex
>> \setupcolors[state=start]
>>
>> \def\graymath{\mframed[frame=off,
>> background=color,
>> backgroundcolor=lightgray,
>> backgroundoffset=2pt
>> ]}
>>
>> \starttext
>>
>> Since for $|x| < 1$ we have
>> \startformula
>> \log(1+x) = \graymath{x- \displaystyle{x^2\over2}} + {x^3 \over 3} + \cdots
>> \stopformula
>> we may write $\log(1+x) = x + O(x^2)$.
>>
>> \stoptext
>> %%%% end mframed-example.tex
>
> Search for "Alignment in inmframed" in the mailing list archives.
>
> % The next statement is part of the core. Included it here for % illustration.
>
> \definemathframed[mcframed] [location=mathematics]
>
> \starttext
>
> \startformula
> \ln (1+x) =
> \mcframed[background=color,backgroundcolor=red,foregroundcolor=white,frame=off]{x
> - {\frac {x^2}{\frac{x^3}{\frac{x^3}{3}}}}} +
> \frac{x^3}{3}-\cdots.
> \stopformula
>
> \startformula
> \ln (1+x) = \mcframed{x - {\frac {x^2}{\frac{x^3}{\frac{x^3}{3}}}}} +
> \frac{x^3}{3}-\cdots.
> \stopformula
>
> \stoptext
>
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