After poking around for a bit, I was wondering if there was a faster method for the following:
# Array of index values 0..n items = numpy.array([0,3,2,1,4,2],dtype=int) # Count the number of occurrences of each index counts = numpy.zeros(5, dtype=int) for i in items: counts[i] += 1 In my real code, 'items' contain up to a million values and this loop will be in a performance critical area of code. If there is no simple solution, I can trivially code this using the C-API. Thanks, -Kevin
_______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion
