On Thu, May 22, 2008 at 8:59 AM, Kevin Jacobs <[EMAIL PROTECTED]> <[EMAIL PROTECTED]> wrote: > After poking around for a bit, I was wondering if there was a faster method > for the following: > > # Array of index values 0..n > items = numpy.array([0,3,2,1,4,2],dtype=int) > > # Count the number of occurrences of each index > counts = numpy.zeros(5, dtype=int) > for i in items: > counts[i] += 1 > > In my real code, 'items' contain up to a million values and this loop will > be in a performance critical area of code. If there is no simple solution, > I can trivially code this using the C-API.
How big is n? If it is much smaller than a million then loop over that instead. _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion
