On 6/4/2009 10:50 AM josef.p...@gmail.com apparently wrote: > intersect1d gives set intersection if both arrays have > only unique elements (i.e. are sets). I thought the > naming is pretty clear:
> intersect1d(a,b) set intersection if a and b with unique elements > intersect1d_nu(a,b) set intersection if a and b with non-unique elements > setmember1d(a,b) boolean index array for a of set intersection if a > and b with unique elements > setmember1d_nu(a,b) boolean index array for a of set intersection if > a and b with non-unique elements >>> a array([1, 1, 2, 3, 3, 4]) >>> b array([1, 4, 4, 4]) >>> np.intersect1d_nu(a,b) array([1, 4]) That is, intersect1d_nu is the actual set intersection function. (I.e., intersect1d and intersect1d_nu would most naturally have swapped names.) That is why the appended _nu will not communicate what was intended. (I.e., setmember1d_nu will not be a match for intersect1d_nu.) Cheers, Alan Isaac _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
