Well, they aren't quite the same. If a is the length of A, and b is the length of B, then a*b = A dot B* cos (theta). I'm still not familiar enough with numpy or math to know if there's some function that will produce a from A. It's easy enough to do, a = A(0)**2 + ..., but I would like to think it's a common enough need that there would be something available like sumsq().
Keith Goodman wrote: > On Fri, Dec 18, 2009 at 3:22 PM, Wayne Watson > <sierra_mtnv...@sbcglobal.net> wrote: > >> Is there a scalar product in numpy? >> > > Isn't that the same thing as a dot product? np.dot doesn't do what you want? > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > http://mail.scipy.org/mailman/listinfo/numpy-discussion > > -- Wayne Watson (Watson Adventures, Prop., Nevada City, CA) (121.015 Deg. W, 39.262 Deg. N) GMT-8 hr std. time) Obz Site: 39° 15' 7" N, 121° 2' 32" W, 2700 feet "... humans'innate skills with numbers isn't much better than that of rats and dolphins." -- Stanislas Dehaene, neurosurgeon Web Page: <www.speckledwithstars.net/> _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion