On Thu, May 27, 2010 at 6:02 AM, Vincent Davis <vinc...@vincentdavis.net> wrote:
>
> On Thu, May 27, 2010 at 1:27 AM, Francesc Alted <fal...@pytables.org> wrote:
>>
>> A Thursday 27 May 2010 05:52:22 Vincent Davis escrigué:
>> > How do I determine if an array's (or column in a structured array) dtype is
>> > a number or a string. I see how to determine the actual dtype but all I
>> > want to know is if it is a string or a number.
>>
>> I suppose that the `.kind` attribute of dtype would help you:
>>
>> In [2]: s = np.dtype("S3")
>>
>> In [4]: s.kind
>> Out[4]: 'S'
>>
>> In [5]: i = np.dtype("i4")
>>
>> In [6]: i.kind
>> Out[6]: 'i'
>>
>> In [7]: f = np.dtype("f8")
>>
>> In [8]: f.kind
>> Out[8]: 'f'
>
> I know about this but the problem is that while the fist example is usable,
> the others are not great because to know that it is a number I would need to
> do something like(see below) but I might miss a number dtype,
> def is_number(obj):
> if obj.dtype.kind in ('i', 'f',..):
> return True
>>
>> Pierre GM "Check `numpy.lib._iotools._is_string_like`"
>
> This is ok, but I am having problem making it work, I keep getting an error
> that I am giving it 2 items and it only takes 1. Obviously I think I am
> giving it 1. This of course tells me if it is string like but not that "is" a
> number.
> Thanks
> Vincent
To see if it is a number could you use something like:
np.issubdtype(a.dtype, float) or np.issubdtype(a.dtype, int) or
np.issubdtype(a.dtype, complex)
And for string:
np.issubdtype(a.dtype, str)
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