On 8 Sep 2014 10:42, "Sturla Molden" <sturla.mol...@gmail.com> wrote: > > Stefan Otte <stefan.o...@gmail.com> wrote: > > > stack([[a, b], [c, d]]) > > > > In my case `stack` replaced `hstack` and `vstack` almost completely. > > > > If you're interested in including it in numpy I created a pull request > > [1]. I'm looking forward to getting some feedback! > > As far as I can see, it uses hstack and vstack. But that means a and b have > to have the same number of rows, c and d must have the same rumber of rows, > and hstack((a,b)) and hstack((c,d)) must have the same number of columns. > > Thus it requires a regularity like this: > > AAAABB > AAAABB > CCCDDD > CCCDDD > CCCDDD > CCCDDD > > What if we just ignore this constraint, and only require the output to be > rectangular? Now we have a 'tetris game': > > AAAABB > AAAABB > CCCCBB > CCCCBB > CCCCDD > CCCCDD > > or > > AAAABB > AAAABB > CCCCBB > CCCCBB > CCCCBB > CCCCBB > > This should be 'stackable', yes? Or perhaps we need another stacking > function for this, say numpy.tetris?
It's not at all obvious to me how to describe such "tetris" configurations, or interpret then unambiguously. Do you have a more detailed specification in mind? > And while we're at it, what about higher dimensions? should there be an > ndstack function too? Same comment here. -n
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