Hi Pablo, I cannot edit the code page, but I can edit the wiki. I added LinkedIn thereto the list of implementations.
Also for java the latest signpost seems to work fine, and other clients in other languages are getting the job done. On Wed, Apr 7, 2010 at 7:24 PM, Pablo Fernandez <fernandezpabl...@gmail.com>wrote: > Hi, > > I've sent a message to the group a few days ago about the inclusion of > a new library to the "code" page. I'm attaching it again at the end of > this mail. > > Please let me know if someone is evaluating the posibility of > including this lib, and if not, why? and what do I have to change in > order to make it comply to your standards (but please do not stay > silent). > > Thanks > > -- > Hi, > > I've developed a new OAuth library for java that is intended to work > with all APIs. It's called Scribe and has been featured in LinkedIn's > developers forums: > > http://developer.linkedin.com/message/4568 > > The library is mature, is being used in production and it's the only > one known to work out of the box with LinkedIn's implementation of > OAuth. > > I'd like to have it's home page (github.com/fernandezpablo85/scribe) > linked to the http://oauth.net/code/ page. > > It would be also a great idea to link LinkedIn's API to the list of > OAuth implementers here: http://wiki.oauth.net/Implementations > > Thanks a lot! > > -- > You received this message because you are subscribed to the Google Groups > "OAuth" group. > To post to this group, send email to oa...@googlegroups.com. > To unsubscribe from this group, send email to > oauth+unsubscr...@googlegroups.com <oauth%2bunsubscr...@googlegroups.com>. > For more options, visit this group at > http://groups.google.com/group/oauth?hl=en. > > -- You received this message because you are subscribed to the Google Groups "OAuth" group. To post to this group, send email to oa...@googlegroups.com. To unsubscribe from this group, send email to oauth+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/oauth?hl=en.
